Law+of+Sines+2A

Sin A / CB Sin C/ AB Sin A/25 Sin 108/ 38 Sin A = sin -1 (25sin(108)/38) Sin A = 38.7
 * 1) 18) in the triangle ABC, m< c= 108, CB = 25 and AB= 38, I need to find the remaining sides and angles in the triangle. (Marjorie G )

Find the measure of <B m<B = 180 - (108+38.7) m<B =33.3

find AC Sin B/ AC Sin A/ BC Sin 33.3 / AC Sin 38.7/25 AC=( 25 sin(33.3)/sin(38.7)) AC= 21.9

19) In the triangle RST, m<S=124, RS= 9.1, and TR= 15.4, I need to find the remaining sides and angles in the triangle. ( Marjorie G ) Find m<T Sin S /RT Sin T/ RS Sin 124/15.4 sin T / 9.1 (9.1 sin (124)/15.4) = sin T Sin-1 ( 9.1sin(124)/15.4 m<T 29.3 = m<T

find m<R m<R = 180-(124+29.3) m<R = 180- 153.3 m<R 26.7

find ST sin T / RS sin R / ST Sin 29.3/9.1 Sin 26.7/ST St = (9.1 Sin (26.7)/Sin 29.3) St = 8.3