Intercepts+2C-1

__Intercepts__
toc How do we find the coordinates of the x and the y-intercepts? The most common way to find the x-intercept(s) is to graph the equation.

Example #1

__Using Algebra__
The coordinates of the X-intercepts will always be (x, 0). In order to find the 'x' value by hand, you need to substitute the y value in your equation with 0 and then use algebra to find the "x" value.

The coordinates of the Y-intercepts will always be (0, y). Substitute the x value in you equation with 0 and then use algebra to find the "y" value.

If you want to find the X and Y for the equation that is in the form of you would first have to factor the equation to have it look like. Once you have done that the first thing to do is to take one of the parenthesis and have it equal 0. Then solve for X to find the value of X in on of the parenthesis and then do the same thing to the other parenthesis to find the value of the other X.

When looking for the value of Y the only thing that you need to do is to substitute the values of the two x's with 0. Then solve.

||= Explanation || math y= x^2 + x -6 math ||  || || Step 1 : Factor the equation. Step 2: Replace 'y' with zero. Step 3: Solve for the first 'x' intercept. || || Step 4: Use the second set of parentheses to find the second 'x' intercept. ||
 * = Example 2
 * Find the x and y intercepts for the equation
 * [[image:Y=(x+3)(x-2).png]]
 * [[image:0=x-2.png]]
 * (2, 0) and (-3,0) || Both of the 'x' values have been found and they were 2 and -3. So the coordinates of the x-intercepts are (2,0) and (-3,0) ||
 * [[image:Y=(0+3).png]] || Step 5: Find the 'y' intercept by replacing all x's and solve. ||
 * (0, -6) || The 'y' value have been found and it was -6. So the coordinates of the y-intercept is (0,-6) ||

__Further Discussion__

 * Why is knowing the coordinates of the x and y intercepts important?