Solve for x
#23
x^2+10x-75=0
(x-5)(x+15)
x= -5 or x= -15

In order to solve this you must find out how many x's are in the equation thus giving you (x )(x )
then you have to find out what two numbers added together equals 10, but at the same time when multiplied together equals -75.
once you find that out your final product should look like this (x-5)(x+15)
If you want to solve for x you have to find a number when multiplied by the numbers you found equals 0

Factoring:

ex #1:
xˆ2-13x+12
Solution:
(x-12) (x-1)

ex #2:
xˆ2-3x-40
Solution:
(x-8) (x+5)

ex #3:
xˆ2-10x+24
Solution:
(x-6) (x-4)

By: Kaloni Baylor
Olivia Billborogh
Arielle Reese

Naima Holland #10
FX-14
a. X2-49
=(X)2- (7)2
=(x+7) (x+7)
b. 4x2-1
=(2x)2-(1)2
=(2x+1) (2x+1)
c. x2y2-81z2
=(xy)2-(9z)2
=(xy+9z) (xy+9z)
d. 2x3-8x
=2x (x2-4)
=2x ((x2)-(2)2)
=2x(x+2) (x+2)

Problem Topic:
Factoring.
Notes:
A Process of separating an equations/formula into its common parts.

Nakkera Walker #19

Solve for x

#23

x^2+10x-75=0

(x-5)(x+15)

x= -5 or x= -15

In order to solve this you must find out how many x's are in the equation thus giving you (x )(x )

then you have to find out what two numbers added together equals 10, but at the same time when multiplied together equals -75.

once you find that out your final product should look like this (x-5)(x+15)

If you want to solve for x you have to find a number when multiplied by the numbers you found equals 0

Factoring:

ex #1:

xˆ2-13x+12

Solution:

(x-12) (x-1)

ex #2:

xˆ2-3x-40

Solution:

(x-8) (x+5)

ex #3:

xˆ2-10x+24

Solution:

(x-6) (x-4)

By: Kaloni Baylor

Olivia Billborogh

Arielle Reese

Naima Holland #10

FX-14

a. X2-49

=(X)2- (7)2

=(x+7) (x+7)

b. 4x2-1

=(2x)2-(1)2

=(2x+1) (2x+1)

c. x2y2-81z2

=(xy)2-(9z)2

=(xy+9z) (xy+9z)

d. 2x3-8x

=2x (x2-4)

=2x ((x2)-(2)2)

=2x(x+2) (x+2)

Problem Topic:

Factoring.

Notes:

A Process of separating an equations/formula into its common parts.